What is the value of 6tan(30)+2sec(45) ?

The value of 6tan(30)+2sec(45) is 2sqrt(3)+2sqrt(2)

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6tan(30)+2sec(45)

6 tan (3 0^{\circ}) + 2 sec (4 5^{\circ})

23 + 22

Decimal Notation

6.29252 \dots

Solution steps

6 tan (3 0^{\circ}) + 2 sec (4 5^{\circ})

Use the following trivial identity:

tan (3 0^{\circ}) = \frac{3}{3}

tan (3 0^{\circ})

tan (x)

periodicity table with

18 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

= \frac{3}{3}

Use the following trivial identity:

sec (4 5^{\circ}) = 2

sec (4 5^{\circ})

sec (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sec (x) 1 \frac{2 3}{3} 22 Undefined - 2 - 2 - \frac{2 3}{3} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sec (x) - 1 - \frac{2 3}{3} - 2 - 2 Undefined 22 \frac{2 3}{3}

= 2

= 6 \cdot \frac{3}{3} + 22

Simplify

6 \cdot \frac{3}{3} + 22 : 23 + 22

6 \cdot \frac{3}{3} + 22

6 \cdot \frac{3}{3} = 23

6 \cdot \frac{3}{3}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 \cdot 6}{3}

Divide the numbers:

\frac{6}{3} = 2

= 23

= 23 + 22

= 23 + 22

8 sin (0.3 (19) - 3) + 74

40 sin (3 7^{\circ})

csc (arcsin (\frac{1}{6}) - arccos (\frac{1}{10}))

3 cos (6 0^{\circ})

tan (117 π)

What is the value of 6tan(30)+2sec(45) ?
The value of 6tan(30)+2sec(45) is 2sqrt(3)+2sqrt(2)