What is the general solution for solvefor x,cos(x)-cos(y)=0 ?

The general solution for solvefor x,cos(x)-cos(y)=0 is x=arccos(cos(y))+2pin,x=-arccos(cos(y))+2pin

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solvefor x,cos(x)-cos(y)=0

solve for

x, cos (x) - cos (y) = 0

x = arccos (cos (y)) + 2 πn, x = - arccos (cos (y)) + 2 πn

Solution steps

cos (x) - cos (y) = 0

Move

cos (y)

to the right side

cos (x) - cos (y) = 0

Add

cos (y)

to both sides

cos (x) - cos (y) + cos (y) = 0 + cos (y)

Simplify

cos (x) = cos (y)

cos (x) = cos (y)

Apply trig inverse properties

cos (x) = cos (y)

General solutions for

cos (x) = cos (y)

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = - arccos (a) + 2 πn

x = arccos (cos (y)) + 2 πn, x = - arccos (cos (y)) + 2 πn

x = arccos (cos (y)) + 2 πn, x = - arccos (cos (y)) + 2 πn

- 3 tan^{2} (θ) + 2 tan (θ) = 6 tan (θ) + 1

sin (x) + cos (x) = - 3

sin (x) = \frac{1}{2}, cos (x) = - \frac{3}{2}

cos (x) = \frac{2 5}{5}

csc (x) = cot (x) - 1

What is the general solution for solvefor x,cos(x)-cos(y)=0 ?
The general solution for solvefor x,cos(x)-cos(y)=0 is x=arccos(cos(y))+2pin,x=-arccos(cos(y))+2pin