What is the general solution for -5cos(5x)=0 ?

The general solution for -5cos(5x)=0 is x= pi/(10)+(2pin)/5 ,x=(3pi}{10}+\frac{2pin)/5

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Popular >

-5cos(5x)=0

Solution

- 5 cos (5 x) = 0

Solution

x = \frac{π}{10} + \frac{2 πn}{5}, x = \frac{3 π}{10} + \frac{2 πn}{5}

Degrees

x = 1 8^{\circ} + 7 2^{\circ} n, x = 5 4^{\circ} + 7 2^{\circ} n

Solution steps

- 5 cos (5 x) = 0

Divide both sides by

- 5

- 5 cos (5 x) = 0

Divide both sides by

- 5

\frac{- 5 cos ( 5 x )}{- 5} = \frac{0}{- 5}

Simplify

cos (5 x) = 0

cos (5 x) = 0

General solutions for

cos (5 x) = 0

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

5 x = \frac{π}{2} + 2 πn, 5 x = \frac{3 π}{2} + 2 πn

5 x = \frac{π}{2} + 2 πn, 5 x = \frac{3 π}{2} + 2 πn

Solve

5 x = \frac{π}{2} + 2 πn : x = \frac{π}{10} + \frac{2 πn}{5}

5 x = \frac{π}{2} + 2 πn

Divide both sides by

5

5 x = \frac{π}{2} + 2 πn

Divide both sides by

5

\frac{5 x}{5} = \frac{\frac{π}{2}}{5} + \frac{2 πn}{5}

Simplify

\frac{5 x}{5} = \frac{\frac{π}{2}}{5} + \frac{2 πn}{5}

Simplify

\frac{5 x}{5} : x

\frac{5 x}{5}

Divide the numbers:

\frac{5}{5} = 1

= x

Simplify

\frac{\frac{π}{2}}{5} + \frac{2 πn}{5} : \frac{π}{10} + \frac{2 πn}{5}

\frac{\frac{π}{2}}{5} + \frac{2 πn}{5}

\frac{\frac{π}{2}}{5} = \frac{π}{10}

\frac{\frac{π}{2}}{5}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{π}{2 \cdot 5}

Multiply the numbers:

2 \cdot 5 = 10

= \frac{π}{10}

= \frac{π}{10} + \frac{2 πn}{5}

x = \frac{π}{10} + \frac{2 πn}{5}

x = \frac{π}{10} + \frac{2 πn}{5}

x = \frac{π}{10} + \frac{2 πn}{5}

Solve

5 x = \frac{3 π}{2} + 2 πn : x = \frac{3 π}{10} + \frac{2 πn}{5}

5 x = \frac{3 π}{2} + 2 πn

Divide both sides by

5

5 x = \frac{3 π}{2} + 2 πn

Divide both sides by

5

\frac{5 x}{5} = \frac{\frac{3 π}{2}}{5} + \frac{2 πn}{5}

Simplify

\frac{5 x}{5} = \frac{\frac{3 π}{2}}{5} + \frac{2 πn}{5}

Simplify

\frac{5 x}{5} : x

\frac{5 x}{5}

Divide the numbers:

\frac{5}{5} = 1

= x

Simplify

\frac{\frac{3 π}{2}}{5} + \frac{2 πn}{5} : \frac{3 π}{10} + \frac{2 πn}{5}

\frac{\frac{3 π}{2}}{5} + \frac{2 πn}{5}

\frac{\frac{3 π}{2}}{5} = \frac{3 π}{10}

\frac{\frac{3 π}{2}}{5}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{3 π}{2 \cdot 5}

Multiply the numbers:

2 \cdot 5 = 10

= \frac{3 π}{10}

= \frac{3 π}{10} + \frac{2 πn}{5}

x = \frac{3 π}{10} + \frac{2 πn}{5}

x = \frac{3 π}{10} + \frac{2 πn}{5}

x = \frac{3 π}{10} + \frac{2 πn}{5}

x = \frac{π}{10} + \frac{2 πn}{5}, x = \frac{3 π}{10} + \frac{2 πn}{5}

Popular Examples

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2 sin (x) tan (x) + 5 = 4 sec (x)

cos^2(x)-cos(x)-2=0,0<= x<= 2pi

cos^{2} (x) - cos (x) - 2 = 0, 0 \leq x \leq 2 π

cos^4(x)-1=0

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sec(x)-cos(x)=sin(x)

sec (x) - cos (x) = sin (x)

2sin(x)=sqrt(3),0<= x<2pi

2 sin (x) = 3, 0 \leq x < 2 π

Frequently Asked Questions (FAQ)

What is the general solution for -5cos(5x)=0 ?
The general solution for -5cos(5x)=0 is x= pi/(10)+(2pin)/5 ,x=(3pi}{10}+\frac{2pin)/5