What is implicit (dy)/(dx),xy-4x=5 ?

The answer to implicit (dy)/(dx),xy-4x=5 is (dy}{dx}=\frac{-y+4)/x

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implicit (dy)/(dx),xy-4x=5

implicit derivative

\frac{d y}{d x}, x y - 4 x = 5

\frac{d y}{d x} = \frac{- y + 4}{x}

Solution steps

x y - 4 x = 5

Treat

y

y (x)

Differentiate both sides:

y + x \frac{d y}{d x} - 4 = 0

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = \frac{- y + 4}{x}

\frac{d y}{d x} = \frac{- y + 4}{x}

\int - cos (2 x) d x

\frac{x ^{2}}{2 - x ^{2}}

\int_{1}^{9} \frac{x - 2}{x} d x

x \to 0 lim (\frac{x}{x ^{2} + 2 x})

\int_{0}^{2} x 7 - x^{2} d x

What is implicit (dy)/(dx),xy-4x=5 ?
The answer to implicit (dy)/(dx),xy-4x=5 is (dy}{dx}=\frac{-y+4)/x