What is the tangent of f(x)=xsqrt(x),(4,8) ?

The tangent of f(x)=xsqrt(x),(4,8) is y=3x-4

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tangent of f(x)=xsqrt(x),(4,8)

tangent of

f (x) = x x, (4, 8)

y = 3 x - 4

Solution steps

Find the slope of

f (x) = x x : \frac{df ( x )}{d x} = \frac{3 x}{2}

Compute the slope of

f (x) = x x

(4, 8) : m = 3

Find the line with slope m=

3

and passing through

(4, 8) : y = 3 x - 4

y = 3 x - 4

x \to 0 lim (1 0^{2 x})

\frac{d}{d x} (120 x)

\int (x + 2) sin^{2} (2 θ)

x \to 0 lim (\frac{4 x ^{2} - 3 x}{x ^{2} + 0.8 x + \frac{4}{x}})

What is the tangent of f(x)=xsqrt(x),(4,8) ?
The tangent of f(x)=xsqrt(x),(4,8) is y=3x-4